By M. J. Iremonger
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5 KN EFFICIENCY 60 7. 75 KN EFFICIENCY 50 % RIVET DIAMETER (MM) - 0 TO STOP» --VE TO CHANGE PLATE DIMENSIONS? 519 7. 25 KN EFFICIENCY 54 7. 625 KN EFFICIENCY 55 % RIVET DIAMETER (MM) - 0 TO STOP» ~VE TO CHANGE PLATE DIMENSIONS? 1 PLATE WIDTH (MM)? 60 PLATE THICKNESS (MM)? 5 RIVET DIAMETER (MM) - 0 TO STOP» -VE TO CHANGE PLATE DIMENSIONS? 2658 7. 5 7. RIVET DIAMETER (MM) 0 TO STOP» -VE TO CHANGE PLATE DIMENSIONS? 3333 Z RIVET DIAMETER (MM) - 0 TO STOP» -VE TO CHANGE PLATE DIMENSIONS? 0 STOP AT LINE 220 READY Program notes (1) The load capacity of the plate (Fl) is calculated in line 160.
NOTE: INPUT ZERO FOR THE UNKNOWN CONSTANT INPUT YOUNG'S MODULUS E (KN/MM''2) ? STOP AT LINE 120 READY Program notes (1) The program interprets a zero input value of any of the constants as indicating that the constant is unknown (lines 130, 180 and 230). (2) line 300 is reached if all three constants are specified. ). 4 Design of circular shaft 43 There is, however, a flaw in the program as written above. It is possible to input zero for two of the constants thereby classifying them as unknown and causing an erroneous prediction of the third constant.
25 INPUT 0(T0 STOP),+VE VALUE(TO SPECIFY DIAMETER)r -VE VALUE(TO SPECIFY THICKNESS)? 5 REQUIRED DIAMETER 60 MM INPUT 0(T0 STOP)»+VE VALUE(TO SPECIFY DIAMETER)» -VE VALUE(TO SPECIFY THICKNESS)? 666667 MM INPUT 0(T0 STOP)f+VE VALUE(TO SPECIFY DIAMETER)» -VE VALUE(TO SPECIFY THICKNESS)? 0 STOP AT LINE 210 READY Program notes (1) Suppose the disc has a diameter d, thickness t and shear strength s. 11) t = pd/4s (2) The program extension which enables individual values of diameter or thickness to be specified starts in line 170.
Basic Stress Analysis by M. J. Iremonger